Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 5 - Section 5.6 - Nuclear Fission and Fusion - Understanding the Concepts - Page 162: 5.61

Answer

$4.4\times10^{3}\,Bq$

Work Step by Step

As $1\,Ci=3.7\times10^{10}\,Bq$ and the prefix nano (n) stands for $10^{-9}$, we have $120\,nCi=120\,nCi\times\frac{10^{-9}}{nano}\times\frac{3.7\times10^{10}\,Bq}{1\,Ci}$ $=4.4\times10^{3}\,Bq$
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