Answer
0.10 microcuries.
Work Step by Step
$3.7\,kBq=3.7\,kBq\times\frac{10^{3}}{kilo}\times\frac{1\,Ci}{3.7\times10^{10}Bq}\times\frac{\mu}{10^{-6}}$
$=0.10\,\mu Ci$
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)
by Timberlake, Karen C.
Published by
Prentice Hall
ISBN 10:
0321908449
ISBN 13:
978-0-32190-844-5
Chapter 5 - Section 5.6 - Nuclear Fission and Fusion - Understanding the Concepts - Page 162: 5.62
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