Answer
$(x+14)(x-11)$
Work Step by Step
$x^2+3x-154$ has no common monomial factors.
=$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$
=$(x+\ \ )(x-\ \ )$ The factors of -154 must have unlike signs.
=$(x+14)(x-11)$ 14 and -11 have a sum of 3 and a product of -154.
