Answer
$(r+5)(r-7)$
Work Step by Step
$r^2-2r-35$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(r\ \ \ \ \ \ )(r\ \ \ \ \ \ )$
$=(r+\ )(r-\ )$ The factors of -35 must have unlike signs.
$=(r+5)(r-7)$ 5 and -7 have a sum of -2 and a product of -35.
