Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 50

Answer

$(y+20)(y-6)$

Work Step by Step

$y2+14y-120$ has no common monomial factor =$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$ =$(y+\ \ )(y-\ \ )$ The factors of -120 must have unlike signs. =$(y+20)(y-6)$ 20 and -6 have a sum of 14 and a product of -120.
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