Answer
$(b+6)(b-5)$
Work Step by Step
$b^2+b-30$ has no common monomial factors
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(b\ \ \ \ \ \ )(b\ \ \ \ \ \ )$
$=(b+\ )(b-\ )$ The factors of -30 must have unlike signs.
$=(b+6)(b-5)$ 6 and -5 have a sum of 1 and a product of -30.
