Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 25

Answer

$(x+4)(x-2)$

Work Step by Step

$x^2+2x-8$ has no common monomial factor. $x^2+2x-8=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $x^2+2x-8=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$ $x^2+2x-8=(x+\ )(x-\ )$ The factors of -8 must have unlike signs. $x^2+2x-8=(x+4)(x-2)$ 4 and -2 have a sum of 2 and a product of -8.
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