Answer
$(a+4)(a+25)$
Work Step by Step
$a^2+29a+100$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(a\ \ \ \ \ \ )(a\ \ \ \ \ \ )$
$=(a+\ )(a+\ )$ All signs in the trinomial are positive.
$=(a+4)(a+25)$ 4 and 25 have a sum of 29 and a product of 100.
