Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 49

Answer

$(a+4)(a+25)$

Work Step by Step

$a^2+29a+100$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(a\ \ \ \ \ \ )(a\ \ \ \ \ \ )$ $=(a+\ )(a+\ )$ All signs in the trinomial are positive. $=(a+4)(a+25)$ 4 and 25 have a sum of 29 and a product of 100.
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