Answer
$(x+14)(x-3)$
Work Step by Step
$x^2+11x-42$ has no common monomial factor
$=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$
$=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$
$=(x+\ )(x-\ )$ The factors of -42 must have unlike signs.
$=(x+14)(x-3)$ 14 and -3 have a sum of 11 and a product of -42.
