Answer
$7(x+2)(x-1)$
Work Step by Step
$7x2+7x-14\longrightarrow$ 7 is a common factor.
=$7(x^2+x-2)$
=$7(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$
=$7(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$
=$7(x+\ \ )(x-\ \ )$ The factors of -2 must have unlike signs.
=$7(x+2)(x-1)$ 2 and -1 have a sum of 1 and a product of -2.
