Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 51

Answer

$(y+5)(y-19)$

Work Step by Step

$y2-14y-95$ has no common monomial factor =$(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$(y\ \ \ \ \ \ \ )(y\ \ \ \ \ \ \ )$ =$(y+\ \ )(y-\ \ )$ The factors of -95 must have unlike signs. =$(y+5)(y-19)$ 5 and -19 have a sum of -14 and a product of -95.
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