Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 68

Answer

$x(x+12)(x-13)$

Work Step by Step

$x^3-x^2-156x\longrightarrow$ x is a common factor. $x(x^2-x-156)$ =$x(\ \ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ \ )$ =$x(x\ \ \ \ \ \ \ )(x\ \ \ \ \ \ \ )$ =$x(x+\ \ )(x+\ \ )$ The factors of -156 must have unlike signs. =$x(x+12)(x-13)$ 12 and -13 have a sum of -1 and a product of -156.
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