Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 35

Answer

$(c+6)(c-3)$

Work Step by Step

$c^2+3c-18$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(c\ \ \ \ \ \ )(c\ \ \ \ \ \ )$ $=(c+\ )(c-\ )$ The factors of -18 must have unlike signs. $=(c+6)(c-3)$ 6 and -3 have a sum of 3 and a product of -18.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.