Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 32

Answer

$(b+6)(b-12)$

Work Step by Step

$b^2-6b-72$ has no common monomial factors $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(b\ \ \ \ \ \ )(b\ \ \ \ \ \ )$ $=(b+\ )(b-\ )$ The factors of -72 must have unlike signs. $=(b+6)(b-12)$ 6 and -12 have a sum of -6 and a product of -72.
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