Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.3 - Finding Binomial Factors - Exercise: 43

Answer

$(x+6)(x-15)$

Work Step by Step

$x^2-9x-90$ has no common monomial factor $=(\ \ \ \ \ \ \ \ )(\ \ \ \ \ \ \ \ )$ $=(x\ \ \ \ \ \ )(x\ \ \ \ \ \ )$ $=(x+\ )(x-\ )$ The factors of -90 must have unlike signs. $=(x+6)(x-15)$ 6 and -15 have a sum of -9 and a product of -90.
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