College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 84

Answer

$\frac{1}{2x+1}$

Work Step by Step

We multiply by $x(x+1)$ to simplify the fractions: $\displaystyle \frac{\frac{1}{x}-\frac{1}{x+1}}{\frac{1}{x}+\frac{1}{x+1}}=\frac{\frac{1}{x}-\frac{1}{x+1}}{\frac{1}{x}+\frac{1}{x+1}}$ * $\displaystyle \frac{x(x+1)}{x(x+1)}=\frac{(x+1)-x}{(x+1)+x}=\frac{1}{2x+1}$
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