College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 88

Answer

$\displaystyle\frac{\sqrt{6}}{2}$

Work Step by Step

We multiply the numerator and denominator by $\sqrt{6}$ to simplify: $\displaystyle \frac{3}{\sqrt{6}}=\frac{3}{\sqrt{6}}*\frac{\sqrt{6}}{\sqrt{6}}=\frac{3\sqrt{6}}{6}=\frac{\sqrt{6}}{2}$
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