College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 75

Answer

$\dfrac{x-3}{2x+3}$

Work Step by Step

Factor each polynomial to obtain: $=\dfrac{(x-3)(x+1)}{(2x+3)(x+1)}$ Cancel the common factors to obtain: $\require{cancel} \\=\dfrac{(x-3)\cancel{(x+1)}}{(2x+3)\cancel{(x+1)}} \\=\dfrac{x-3}{2x+3}$
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