Answer
$\dfrac{x-3}{2x+3}$
Work Step by Step
Factor each polynomial to obtain:
$=\dfrac{(x-3)(x+1)}{(2x+3)(x+1)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{(x-3)\cancel{(x+1)}}{(2x+3)\cancel{(x+1)}}
\\=\dfrac{x-3}{2x+3}$
