Answer
$2x^3-6x^2+4x$
Work Step by Step
Square the binomial using the formula $(a-b)^2=a^2-2ab+b^2$ with $a=x$ and $b=2$ to obtain:
$=x^2(x-2)+x[x^2-2(x)(2) + 2^2]
\\=x^2(x-2)+x(x^2-4x+4)$
Distribute $x^2$ and $x$ to obtain:
$=x^2(x) -x^2(2) + x(x^2) -x(4x)+x(4)
\\=x^3-2x^2+x^3-4x^2+4x$
Combine like terms to obtain:
$=(x^3+x^3) + (-2x^2-4x^2) + 4x
\\=2x^3-6x^2+4x$
