Answer
$\dfrac{x^2+x-1}{x+1}$
Work Step by Step
The LCD of the rational expressions is $x+1$.
Make the expressions similar using their LCD to obtain:
$=\dfrac{x(x+1)}{x+1} - \dfrac{1}{x+1}
\\=\dfrac{x(x)+x(1)}{x+1}- \dfrac{1}{x+1}
\\=\dfrac{x^2+x}{x+1}-\dfrac{1}{x+1}$
Subtract the numerators together and copy the denominator to obtain:
$=\dfrac{x^2+x-1}{x+1}$
