College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 83

Answer

$\frac{-1}{2x}$

Work Step by Step

We find a common denominator for the top fractions, then simplify: $\displaystyle \frac{\frac{1}{x}-\frac{1}{2}}{x-2}=\frac{\frac{2}{2x}-\frac{x}{2x}}{x-2}=\frac{\frac{2-x}{2x}}{x-2}=\frac{2-x}{2x(x-2)}=\frac{2-x}{-2x(2-x)}=\frac{-1}{2x}$
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