Answer
$x=1$
Work Step by Step
$(x+2)^{2}=(x-4)^{2}$
$x^2+4x+4=x^2-8x+16$
$x^2-x^2+4x+8x+4-16=0$
$12x-12=0$
$12x=12$
$x=12/12=1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 114
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