College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 114

Answer

$x=1$

Work Step by Step

$(x+2)^{2}=(x-4)^{2}$ $x^2+4x+4=x^2-8x+16$ $x^2-x^2+4x+8x+4-16=0$ $12x-12=0$ $12x=12$ $x=12/12=1$
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