Answer
$(x^{2}+2)(x+1)(x-1)$
Work Step by Step
We treat $x^4$ as $(x^2)^2$. Then we use $a^2-b^2=(a+b)(a-b)$:
$x^{4}+x^{2}-2=(x^{2})^{2}+x^{2}-2=(x^{2}+2)(x^{2}-1)=(x^{2}+2)(x+1)(x-1)$
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