Answer
$(x-2)(4x^2+3)$
Work Step by Step
Group the first two terms and the last two terms to obtain:
$=(4x^3-8x^2)+(3x-6)$
Factor out the GCF in each group ($4x^2$ in the first and $3$ in the second) to obtain:
$=4x^2(x-2) + 3(x-2)$
Factor out the GCF $x-2$ to obtain:
$=(x-2)(4x^2+3)$
