Answer
$x=-2\pm\sqrt{2}$
Work Step by Step
We solve the equation:
$(x+2)^{2}-2=0$
$(x+2)^{2}=0+2=2$
$x+2=\pm\sqrt{2}$
$x=-2\pm\sqrt{2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 120
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