Answer
$x=\pm 8$
Work Step by Step
We solve the equation:
$x^{2/3}-4=0$
$(x^{1/3})^{2}=0+4=4$
$x^{1/3}=\pm\sqrt{4}=\pm 2$
$x=(\pm2)^3=\pm 8$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 122
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