Answer
$F = 6.6\times 10^{-15}~N$
Work Step by Step
We can use Equation (22-9) to find the magnitude of the electrostatic force on the electron:
$F = \vert q \vert~E$
$F = \vert q \vert~\frac{1}{2\pi \epsilon_0}~\frac{p}{z^3}$
$F = (1.6\times 10^{-19}~C)~[\frac{1}{(2\pi)(8.854\times 10^{-12}~C^2/N~m^2)}]~[\frac{3.6\times 10^{-29}~N\cdot m}{(25\times 10^{-9}~m)^3}]$
$F = 6.6\times 10^{-15}~N$
