Answer
$E = 1500~N/C$
Work Step by Step
We can find the magnitude of the electric field:
$F = \vert q \vert~E$
$E = \frac{F}{\vert q \vert}$
$E = \frac{3.0\times 10^{-6}~N}{2.0\times 10^{-9}~C}$
$E = 1500~N/C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 22 - Electric Fields - Problems - Page 656: 41a
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