Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 656: 44b

Answer

The electric field is directed upward.

Work Step by Step

We can find the magnitude of the electric field: $q~E = Mg$ $E = \frac{Mg}{q}$ $E = \frac{(6.64\times 10^{-27}~kg)(9.8~m/s^2)}{(2)(1.6\times 10^{-19}~C)}$ $E = 2.03\times 10^{-7}~N/C$ To balance the gravitational force, the electrostatic force on the particle must be directed upward. Since the alpha particle has a positive charge, the electric field must be directed upward.
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