Answer
$F = 4.8\times 10^{-13}~N$
Work Step by Step
If an ion has a single electron missing, then the charge on the ion is $+1.6\times 10^{-19}~C$
We can find the magnitude of the electrostatic force on the ion:
$F = q~E$
$F = (1.6\times 10^{-19}~C)(3.0\times 10^6~N/C)$
$F = 4.8\times 10^{-13}~N$