Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 656: 42b

Answer

$F = 4.8\times 10^{-13}~N$

Work Step by Step

If an ion has a single electron missing, then the charge on the ion is $+1.6\times 10^{-19}~C$ We can find the magnitude of the electrostatic force on the ion: $F = q~E$ $F = (1.6\times 10^{-19}~C)(3.0\times 10^6~N/C)$ $F = 4.8\times 10^{-13}~N$
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