Answer
$a=3.51\times10^{15}\frac{m}{s^2}$
Work Step by Step
We know that
$E=\frac{F}{q_e}$
or $F=E.q_e$
We also know that $F=ma$.
So the above equation can be written as
$ma=E.q_e$
Rearranging the equation,
$a=\frac{E.q_e}{m}$
Putting the values and solving,
$a=\frac{2\times10^4\times1.6\times10^{-19}}{9.11\times10^{-31}}$
$a=3.51\times10^{15}\frac{m}{s^2}$
