Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 656: 41c

Answer

The electrostatic force on the proton is directed upward.

Work Step by Step

We can find the magnitude of the electric field: $F = \vert q \vert~E$ $E = \frac{F}{\vert q \vert}$ $E = \frac{3.0\times 10^{-6}~N}{2.0\times 10^{-9}~C}$ $E = 1500~N/C$ We can find the magnitude of the force on a proton: $F = q~E$ $F = (1.6\times 10^{-19}~C)(1500~N/C)$ $F = 2.4\times 10^{-16}~N$ When a negative charge is placed in the electric field, there is a downward force on the charge due to the electric field. Therefore, when a positive charge is placed in the electric field, there will be an upward electrostatic force on the charge due to the electric field. Since the charge on a proton is positive, the electrostatic force on the proton is directed upward.
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