Answer
$F = 1.6\times 10^{-26}~N$
Work Step by Step
We can find the magnitude of the gravitational force on the proton:
$F = ma$
$F = (1.67\times 10^{-27}~kg)(9.8~m/s^2)$
$F = 1.6\times 10^{-26}~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 22 - Electric Fields - Problems - Page 656: 41d
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