Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 345: 9

Answer

$M=74.4 g$

Work Step by Step

In the balanced state, net torque is zero; that is, leftward torque is equal to rightward torque. Mathematically: Leftward torque=Rightward torque $2mg(45.5-12)=Mg(50-45.5)$ $2\times5(33.5)=M(4.5)$ $335=M(4.5)$ or $M=\frac{335}{4.5}=74.4 g$ Thus, the mass of meter stick is $74.4g$
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