Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 345: 10b

Answer

$T_2=28 N$

Work Step by Step

We know: $sin\phi=\frac{Perpendicular}{Hypotenuse}$ From the figure, we find: $sin\phi=\frac{T_2}{T_1}$ or $T_2=T_1sin\phi$ Putting in the values, we obtain: $T_2=48.83.sin35^{\circ}=28 N$ $T_2=28 N$
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