Answer
$T_2=28 N$
Work Step by Step
We know:
$sin\phi=\frac{Perpendicular}{Hypotenuse}$
From the figure, we find:
$sin\phi=\frac{T_2}{T_1}$
or $T_2=T_1sin\phi$
Putting in the values, we obtain:
$T_2=48.83.sin35^{\circ}=28 N$
$T_2=28 N$
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