Answer
$T_3 = 57~N$
Work Step by Step
In part (b), we found that $T_2 = 28~N$
The horizontal component $T_{3x} = 28~N$
The vertical component $T_{3y} = 50~N$
We can find $T_3$:
$T_3 = \sqrt{(28~N)^2+(50~N)^2}$
$T_3 = 57~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 12 - Equilibrium and Elasticity - Problems - Page 345: 10c
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