Answer
The force from the ground on each rear wheel is $~~3889~N$
Work Step by Step
In part (a), we found that the force from the ground on each front wheel is $~~2775~N$
Let $F_f$ be the force from the ground on each front wheel.
Let $F_r$ be the force from the ground on each rear wheel.
We can use a force equation to find $F_r$:
$F_{net} = 0$
$2F_f+2F_r-mg = 0$
$2F_r = mg-2F_f$
$F_r = \frac{mg-2F_f}{2}$
$F_r = \frac{(1360~kg)(9.8~m/s^2)-(2)(2775~N)}{2}$
$F_r = 3889~N$
The force from the ground on each rear wheel is $~~3889~N$.
