Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 345: 10a

Answer

$T_1=48.83 N$

Work Step by Step

We know that: $cos\phi=\frac{base}{hypotenuse}$ Using the given figure, we obtain: $cos\phi=\frac{vertical force}{T_1}$ or $T_1=\frac{vertical force}{cos\phi}$ Plugging in the known values, we find: $T_1=\frac{40}{cos35^{\circ}}$ $T_1=48.83 N$
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