Answer
The force from the ground on each front wheel is $~~2775~N$
Work Step by Step
Let the rotation axis be at the position of the rear wheels.
Let $F_f$ be the force from the ground on each front wheel.
We can use a torque equation to find the force from the ground on each front wheel:
$\tau_{net} = 0$
$(2)(3.05~m)(F_f)-(1.27~m)(1360~kg)(9.8~m/s^2) = 0$
$F_f = \frac{(1.27~m)(1360~kg)(9.8~m/s^2)}{(2)(3.05~m)}$
$F_f = 2775~N$
The force from the ground on each front wheel is $~~2775~N$
