Answer
$I = 12.2~kg~m^2$
Work Step by Step
We can find the rotational inertia:
$I = \frac{1}{3}ML^2$
$I = \frac{1}{3}(\frac{10.0~N}{9.8~m/s^2})(6.00~m)^2$
$I = 12.2~kg~m^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 326: 82a
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