Answer
The magnitude of the linear acceleration is $~~4.11~m/s^2$
Work Step by Step
We can find the linear acceleration as:
$v^2 = v_i^2+2ax$
$a = \frac{v^2 - v_i^2}{2x}$
$a = \frac{0 - (43.0~m/s)^2}{(2)(225~m)}$
$a = -4.11~m/s^2$
The magnitude of the linear acceleration is $~~4.11~m/s^2$
