Answer
$L = 6.65\times 10^{-5}~kg~m^2/s$
Work Step by Step
By the right hand rule, the direction of the angular momentum of each particle about the point is in the same direction. To find the magnitude of the angular momentum of the system, we can add the magnitude of the angular momentum of each particle.
We can find the magnitude of the angular momentum of the system:
$L = 2\times r_{\perp}~mv$
$L = (2)(0.021~m)(2.90\times 10^{-4}~kg)(5.46~m/s)$
$L = 6.65\times 10^{-5}~kg~m^2/s$
