Answer
The magnitude of the torque is $~~2.55~N\cdot m$
Work Step by Step
In part (b), we found that the magnitude of the angular acceleration is $~~16.4~rad/s^2$
We can find the magnitude of the torque:
$\tau = I~\alpha$
$\tau = (0.155~kg~m^2)(16.4~rad/s^2)$
$\tau = 2.55~N\cdot m$
The magnitude of the torque is $~~2.55~N\cdot m$
