Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 326: 74

Answer

The angular speed is zero at time $~~t=12~s$

Work Step by Step

Since the initial angular momentum is positive, the applied torque must be negative since it reverses the rotation. We can find the required time $t$ for the torque to change the angular momentum to $0$: $\tau~t = \Delta L$ $t = \frac{\Delta L}{\tau}$ $t = \frac{-600~kg~m^2/s}{-50~N\cdot m}$ $t = 12~s$ The angular momentum is zero, and thus the angular speed is zero, at time $~~t=12~s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.