Answer
$\frac{d\mathscr{l}}{dt} = (2.0~N\cdot m)~\hat{i}-(4.0~N\cdot m)~\hat{j}$
Work Step by Step
We can find $\frac{d\mathscr{l}}{dt}$ in unit-vector notation:
$\frac{d\mathscr{l}}{dt} = \tau_1+\tau_2$
$\frac{d\mathscr{l}}{dt} = (2.0~N\cdot m)~\hat{i}-(4.0~N\cdot m)~\hat{j}$