Answer
$\tau = 3.0~N\cdot m$
Work Step by Step
We can find the magnitude of the torque on the particle about the origin:
$\tau = r \times F$
$\tau = r F~sin~\theta_3$
$\tau = (3.0~m)(2.0~N)~sin~30^{\circ}$
$\tau = 3.0~N\cdot m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 322: 26c
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
