Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 322: 31c

Answer

$\tau = -7.84~N\cdot m$

Work Step by Step

We can find the torque about $P$: $\tau = r \times F$ $\tau = r_{\perp} mg$ $\tau = (2.00~m) (0.400~kg)(-9.8~m/s^2)$ $\tau = -7.84~N\cdot m$
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