Answer
The tension in the cord is $~~380~N$
Work Step by Step
In part (a), we found that the magnitude of the acceleration is $6.53~m/s^2$
We can use Newton's Second Law to find the tension $F_T$ in the cord:
$Mg-F_T = Ma$
$F_T = Mg-Ma$
$F_T = M~(g-a)$
$F_T = (116~kg)~(9.8~m/s^2-6.53~m/s^2)$
$F_T = 380~N$
The tension in the cord is $~~380~N$
