Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 322: 18f

Answer

Since the mass of this yo-yo is larger than the mass of the San Francisco yo-yo, the tension in the cord of this yo-yo is greater than that of the San Francisco yo-yo.

Work Step by Step

In part (e), we found that the magnitude of the acceleration is $6.53~m/s^2$ We can use Newton's Second Law to find the tension $F_T$ in the cord: $Mg-F_T = Ma$ $F_T = Mg-Ma$ $F_T = M~(g-a)$ $F_T = (M)~(9.8~m/s^2-6.53~m/s^2)$ $F_T = (M)~(3.27~m/s^2)$ Since the mass of this yo-yo is larger than the mass of the San Francisco yo-yo, the tension in the cord of this yo-yo is greater than that of the San Francisco yo-yo.
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