Answer
The magnitude of the linear acceleration is $~~0.13~m/s^2$
Work Step by Step
We can use Equation (11-10) to find the magnitude of the linear acceleration:
$a = \frac{g~sin~\theta}{1+I/MR^2}$
$a = \frac{(9.8~m/s^2)~sin~90^{\circ}}{1+\frac{950~g~cm^2}{(120~g)(0.32~cm)^2}}$
$a = 0.13~m/s^2$
The magnitude of the linear acceleration is $~~0.13~m/s^2$.
